A hydrogen atom and a neutron fuse to form deuterium.If the energy released is 3.6 × 10^-13 J,what is the mass of the deuterium? Take the H atom nucleus as a single proton. A)3.3 × 10^-27 kg B)3.4 × 10^-27 kg C)2.0 × 10^-30 kg D)1.3 × 10^-27 kg

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Quizplus · Accepted Answer

The mass of the deuterium is equal to the mass of the hydrogen atom plus the mass of the neutron, minus the energy released in the fusion reaction. The energy released is given by E = mc^2, where m is the mass and c is the speed of light. Therefore, the mass of the deuterium is:m = (m_H + m_n) - (E/c^2)= (1.673 × 10^-27 kg + 1.693 × 10^-27 kg) - (3.6 × 10^-13 J / (3 × 10^8 m/s)^2)= 3.366 × 10^-27 kg= 3.3 × 10^-27 kg (to two significant figures)

A Hydrogen Atom and a Neutron Fuse to Form Deuterium