Lead(II)iodide,PbI₂,is an ionic compound with a solubility product constant K_sp of 7.9 $\times$ 10^-⁹.Calculate the solubility of this compound in
a.pure water.
b.0.50 mol L^-1 KI solution.

Question

Lead(II)iodide,PbI₂,is an ionic compound with a solubility product constant K_sp of 7.9 $\times$ 10^-⁹.Calculate the solubility of this compound in a.pure water. b.0.50 mol L^-1 KI solution.

Quizplus · Accepted Answer

The Answer of Lead(II)iodide,PbI₂,is an ionic compound with a solubility product constant K_sp of 7.9 $\times$ 10^-⁹.Calculate the solubility of this compound in a.pure water. b.0.50 mol L^-1 KI solution.

Lead(II)iodide,PbI2,is an Ionic Compound with a Solubility Product Constant Ksp ×\times×

Lead(II)iodide,PbI₂,is an Ionic Compound with a Solubility Product Constant K_sp $\times$