What is the freezing point of an aqueous 1.36 m NaCl solution? (K_fp for water is 1.858°C/m.)Assume no ion pairing occurs. A) 5.1°C B) 2.5°C C) -5.1°C D) 0.0°C E) -2.5°C

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Quizplus · Accepted Answer

The freezing point depression can be calculated using the formula ΔTf = i * Kfp * m, where i is the van't Hoff factor (2 for NaCl), Kfp is the freezing point depression constant (1.858°C/m for water), and m is the molality (1.36 m). ΔTf = 2 * 1.858°C/m * 1.36 m = 5.05°C. The freezing point of pure water is 0°C, so the freezing point of the solution is 0°C - 5.05°C = -5.1°C.

What Is the Freezing Point of an Aqueous 1