What mass of ethylene glycol,when mixed with 225 g H₂O,will reduce the equilibrium vapor pressure of H₂O from 1.00 atm to 0.800 atm at 100 $\circ$ C? The molar masses of water and ethylene glycol are 18.02 g/mol and 62.07 g/mol,respectively.Assume ideal behavior for the solution. A) 15.6 g B) 49.9 g C) 194 g D) 969 g E) 3.10 $\times$ 10³ g

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Quizplus · Accepted Answer

The vapor pressure lowering can be calculated using Raoult's Law. The mole fraction of water is needed to reduce the vapor pressure to 0.800 atm. Using the formula for mole fraction and the given molar masses, the mass of ethylene glycol required is calculated to be approximately 194 g.

What Mass of Ethylene Glycol,when Mixed with 225 G H2O,will ∘\circ∘

What Mass of Ethylene Glycol,when Mixed with 225 G H₂O,will $\circ$