If the de Broglie wavelength of an electron is 44 nm,what is its velocity? The mass of an electron is 9.11 $\times$ 10^-31 kg. A) 6.0 $\times$ 10^-5 m/s B) 1.2 $\times$ 10³ m/s C) 1.7 $\times$ 10⁴ m/s D) 3.1 $\times$ 10¹⁰ m/s E) 4.8 $\times$ 10²² m/s

Question

Quizplus · Accepted Answer

The de Broglie wavelength of an electron can be calculated using the equation λ = h/p, where λ is the wavelength, h is Planck's constant, and p is the momentum. Since momentum is equal to mass times velocity, we can rearrange the equation to solve for velocity: v = p/m = h/(mλ).

Plugging in the given values, we get:
v = (6.626 x 10^-34 J.s) / [(9.11 x 10^-31 kg) x (44 x 10^-9 m)]
v ≈ 1.7 x 10^6 m/s

Therefore, the answer is C).

If the De Broglie Wavelength of an Electron Is 44 ×\times×

If the De Broglie Wavelength of an Electron Is 44 $\times$