What is the binding energy of an electron in a photosensitive metal (in kJ/mol)if the longest wavelength of light that can eject electrons from the metal is 205 nm? A) 279 kJ/mol B) 584 kJ/mol C) 792 kJ/mol D) 1.71 $\times$ 10¹⁹ kJ/mol E) 5.84 $\times$ 10^-20 kJ/mol

Question

Quizplus · Accepted Answer

We can use the equation E=h*c/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of light. 
First, we need to convert the longest wavelength to meters:
205 nm = 205*10^-9 m
Then, we can plug in the values and solve for the energy of the photon:
E = (6.626*10^-34 J*s)(3.00*10^8 m/s)/(205*10^-9 m) = 9.651*10^-19 J
Finally, we can convert the energy to kJ/mol using Avogadro's constant:
9.651*10^-19 J/mol * 1 kJ/1000 J * 6.022*10^23 mol^-1 = 5.84 kJ/mol
Therefore, the answer is B) 584 kJ/mol.

What Is the Binding Energy of an Electron in a Photosensitive