For a proton (mass = 1.673 $\times$ 10^-27 kg)moving with a velocity of 2.83 $\times$ 10⁴ m/s,what is the de Broglie wavelength (in pm)? A) 0.356 pm B) 3.56 pm C) 14.0 pm D) 7.15 pm E) 28.5 pm

Question

Quizplus · Accepted Answer

The de Broglie wavelength is given by λ = h/p, where h is Planck's constant and p is the momentum of the proton. 
p = mv = (1.673 x 10^-27 kg) x (2.83 x 10^4 m/s) = 4.745 x 10^-20 kg m/s 
λ = h/p = (6.626 x 10^-34 J s)/(4.745 x 10^-20 kg m/s) = 1.398 x 10^-14 m = 14.0 pm.

Therefore, the best choice is C.

For a Proton (Mass = 1 ×\times× 10-27 Kg)moving with a Velocity of 2

For a Proton (Mass = 1 $\times$ 10^-27 Kg)moving with a Velocity of 2