If a hydrogen atom in the excited n = 4 state relaxes to the ground state,what is the maximum number of possible emission lines?
A) 1
B) 3
C) 6
D) 8
E) infinite

Question

Quizplus · Accepted Answer

When the hydrogen atom in the excited n=4 state relaxes to the ground state, it releases energy in the form of photons of different wavelengths. The maximum number of possible emission lines can be calculated using the formula:

Maximum number of emission lines = n*(n-1)/2

where n is the principal quantum number of the excited state. In this case, n=4, so the maximum number of emission lines can be calculated as:

Maximum number of emission lines = 4*(4-1)/2 = 6

Therefore, the correct answer is C) 6.

If a Hydrogen Atom in the Excited N = 4