Al₂O₃(s)dissolves in aqueous acid to produce A)Al(OH₂)₆³⁺(aq). B)Al(OH)₄^-(aq)and O₂(g). C)Al(OH)₄^-(aq). D)Al(OH₂)₆³⁺(aq)and H₂(g). E)Al(OH)₄^-(aq)and H₂(g).

Question

Quizplus · Accepted Answer

The given compound contains aluminum sulfate, which can be written as Al2(SO4)3. In aqueous acid, the sulfate ion (SO4 2-) will react with H+ to form H2SO4, while the aluminum ion (Al3+) will react with water to form Al(OH)3, which then reacts with excess acid to form Al(OH)2+ and H2O. Therefore, the overall reaction can be written as:
Al2(SO4)3(s) + 6H+(aq) → 2Al(OH)2+(aq) + 3H2SO4(aq)
Simplifying the products gives the answer A, Al(OH)12+ and H2SO4.

Al2O3(s)dissolves in Aqueous Acid to Produce

Al₂O₃(s)dissolves in Aqueous Acid to Produce