An ideal spring with a spring constant of $22 \mathrm {~N} / \mathrm { m }$ is stretched from equilibrium to 2.9 m.How much work is done in the process?
A)93 J
B)186 J
C)47 J
D)121 J

Question

Quizplus · Accepted Answer

The work done on a spring is given by the formula $ W = \frac{1}{2} k x^2 $, where $ k $ is the spring constant and $ x $ is the displacement. Substituting the given values, $ W = \frac{1}{2} \times 22 \times (2.9)^2 = 92.57 \approx 93 $ J.

An Ideal Spring with a Spring Constant Of 22 N/m22 \mathrm {~N} / \mathrm { m }22 N/m

An Ideal Spring with a Spring Constant Of $22 \mathrm {~N} / \mathrm { m }$