It takes 87 J of work to stretch an ideal spring from 1.4 m to 2.9 m from equilibrium.What is the value of the spring constant of this spring?
A)27 N/m
B)77 N/m
C)52 N/m
D)39 N/m

Question

Quizplus · Accepted Answer

The work done in stretching a spring is given by W = (1/2)kx^2, where k is the spring constant and x is the displacement from equilibrium. In this case, W = 87 J, x = 2.9 m - 1.4 m = 1.5 m, so k = 2W/x^2 = 2(87 J)/(1.5 m)^2 = 27 N/m.

It Takes 87 J of Work to Stretch an Ideal