According to Heisenberg,as the uncertainty in the measurement of a particle's momentum is reduced by a factor of 2,by what factor is the uncertainty in that same particle's position changed?
A)1/2
B)1
C)2
D)4

Question

Quizplus · Accepted Answer

According to Heisenberg's uncertainty principle, the product of the uncertainties in a particle's position and momentum is constant. Mathematically, Δx * Δp ≥ h/4π, where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is Planck's constant. If Δp is reduced by a factor of 2, then it becomes Δp/2. We can rearrange the above equation to solve for Δx: Δx ≥ h/4πΔp. If Δp is reduced by a factor of 2, then Δx must be doubled to maintain the same minimum uncertainty according to the inequality. Therefore, the uncertainty in position changes by a factor of 2.

According to Heisenberg,as the Uncertainty in the Measurement of a Particle's