The "seeing" ability or resolution of radiation is determined by its wavelength.If the size of an atom is approximately 1.3 × 10−¹⁰ m,how fast must an electron travel to have a wavelength smaller than that of an atom? (m_e = 9.11 × 10−³¹ kg and h = 6.63 × 10−³⁴ J⋅s) A)5.6E+6 m/s B)5.1E+7 m/s C)8.4E+5 m/s D)9.5E+6 m/s E)2.4E+3 m/s

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To determine the velocity of an electron required for its wavelength to be smaller than the size of an atom, we use the de Broglie wavelength formula: λ = h / (mv), where λ is the wavelength, h is Planck's constant (6.63 × 10^-34 J⋅s), m is the mass of the electron (9.11 × 10^-31 kg), and v is the velocity of the electron. Rearranging the formula to solve for v gives us v = h / (mλ). Given that λ must be smaller than the size of an atom (~1.3 × 10^-10 m), we choose a value for λ just smaller than this size to ensure the electron's wavelength is indeed smaller. Substituting the given values into the rearranged formula and solving for v will yield a result that matches choice A, 5.6E+6 m/s, as the required velocity.

The "Seeing" Ability or Resolution of Radiation Is Determined by Its