What is the molarity of a NaOH solution if 15.5 mL of a 0.220 M H₂SO₄solution is required to neutralize a 25.0-mL sample of the NaOH solution? A)0.273 B)0.355 C)0.710 D)42.6 E)0.136

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Quizplus · Accepted Answer

The molarity of the NaOH solution can be calculated using the formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the acid, and M2 and V2 are the molarity and volume of the base. Given M1 = 0.220 M, V1 = 15.5 mL, and V2 = 25.0 mL, solving for M2 gives M2 = (M1V1)/V2 = (0.220 M * 15.5 mL) / 25.0 mL = 0.273 M.

What Is the Molarity of a NaOH Solution If 15