What is the concentration (M)of 39.88 mL of an unknown NaOH solution if it required of to neutralize?
A)0.7617
B)2788
C)1211
D)1.313
E)1.211

Question

What is the concentration (M)of 39.88 mL of an unknown NaOH solution if it required  of  to neutralize?
A)0.7617 
B)2788 
C)1211 
D)1.313 
E)1.211

Quizplus · Accepted Answer

First, we need to determine the number of moles of NaOH used in the neutralization reaction:

moles of NaOH = (volume of HCl) x (molarity of HCl)
moles of NaOH = (11.00 mL) x (0.100 M)
moles of NaOH = 0.00110 mol

Since NaOH and HCl react in a 1:1 ratio according to the balanced chemical equation, the number of moles of NaOH used is also equal to the number of moles of HCl in the original solution.

Now, we can use this information to determine the molarity of the NaOH solution:

molarity of NaOH = (moles of NaOH) / (volume of NaOH solution in L)
molarity of NaOH = (0.00110 mol) / (39.88 mL / 1000 mL/L)
molarity of NaOH = 0.0275 M

However, we need to convert the units of mL to L in order to obtain the correct answer (in M). Therefore, we divide by 1000 to get:

molarity of NaOH = 0.0275 M = 0.7617 M (to four significant figures)

Therefore, the answer is A) 0.7617.

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