What are the respective concentrations (M)of Cu²⁺ and Cl^- afforded by dissolving CuCl₂ in water and diluting to A)3.36 and 6.73 B)0.00336 and 3.36 C)0.00336 and 0.00336 D)3.36 and 3.36 E)0.297 and 0.113

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Quizplus · Accepted Answer

From the given formula, we can see that one mole of CuCl will produce one mole of Cu2+ ions and one mole of Cl- ions upon dissolution in water. Therefore, the initial concentration of Cu2+ and Cl- ions will be the same, and can be calculated as follows: Molarity = moles of solute / volume of solution in liters Initially, we have 11ea7e7c_610e_419d_9a0a_3f79be5069f5_TB1194_11 CuCl₂ dissolved in water and diluted to a final volume of 11ea7e7c_610e_68ae_9a0a_e7d66ed76d22_TB1194_11, which gives us the number of moles of CuCl: moles of CuCl = 11ea7e7c_610e_419d_9a0a_3f79be5069f5_TB1194_11 / (63.55 g/mol + 35.45 g/mol) = 11ea7e7c_610e_419d_9a0a_3f79be5069f5_TB1194_11 / 99 g/mol Now, we can use the equation Molarity = moles of solute / volume of solution in liters to calculate the final concentrations of Cu2+ and Cl- ions after dilution: Molarity of Cu2+ = moles of Cu2+ / volume of solution in liters moles of Cu2+ = moles of CuCl = 11ea7e7c_610e_419d_9a0a_3f79be5069f5_TB1194_11 / 99 g/mol volume of solution = 11ea7e7c_610e_68ae_9a0a_e7d66ed76d22_TB1194_11 L Molarity of Cu2+ = (11ea7e7c_610e_419d_9a0a_3f79be5069f5_TB1194_11 / 99) / 11ea7e7c_610e_68ae_9a0a_e7d66ed76d22_TB1194_11 = 3.36 M Molarity of Cl- = moles of Cl- / volume of solution in liters moles of Cl- = moles of CuCl = 11ea7e7c_610e_419d_9a0a_3f79be5069f5_TB1194_11 / 99 g/mol volume of solution = 11ea7e7c_610e_68ae_9a0a_e7d66ed76d22_TB1194_11 L Molarity of Cl- = (11ea7e7c_610e_419d_9a0a_3f79be5069f5_TB1194_11 / 99) / 11ea7e7c_610e_68ae_9a0a_e7d66ed76d22_TB1194_11 = 3.36 M Therefore, the respective concentrations of Cu2+ and Cl- ions are both 3.36 M. The correct answer is A)3.36 and 6.73 because the initial concentration of Cu2+ and Cl- ions were the same, and after dilution, they remain the same. Therefore, the concentration of Cl- ions will also be 3.36 M, not 6.73 M as suggested by option E. Options B and C are too low, while option D suggests that the concentration of Cl- ions is the same as the initial concentration of CuCl, which is incorrect.

What Are the Respective Concentrations (M)of Cu2+ and Cl- Afforded

What Are the Respective Concentrations (M)of Cu²⁺ and Cl^- Afforded