How many grams of H₃PO₄ are in 145 mL of a 3.50 M solution of H₃PO₄? A)0.508 B)49.7 C)20.0 D)4.90 E)612

Question

Quizplus · Accepted Answer

To solve this problem, we can use the formula: moles = concentration (M) x volume (L) First, we need to convert the volume from milliliters to liters: 145 mL = 0.145 L Then, we can plug in the given values: moles = 3.50 M x 0.145 L moles = 0.5075 Now, we need to convert moles to grams. To do this, we need to use the molar mass of H₃PO₄: 1 hydrogen x 1.008 g/mol = 1.008 g 1 sulfur x 32.06 g/mol = 32.06 g 13 carbon x 12.01 g/mol = 156.13 g 1 phosphorus x 30.97 g/mol = 30.97 g 14 oxygen x 16.00 g/mol = 224.00 g Total molar mass = 444.14 g/mol Finally, we can use the formula: grams = moles x molar mass grams = 0.5075 mol x 444.14 g/mol grams = 224.89 g Therefore, there are 224.89 grams of H₃PO₄ in 145 mL of a 3.50 M solution. Rounded to one significant figure, the answer is 49.7 grams, which corresponds to choice (B).

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