Why is $\Delta$_T always less than $\Delta$_O? A) There are two more ligands surrounding the metal. B) There are two fewer ligands surrounding the metal. C) The d-orbitals do not point directly at the ligands. D) None of the above. E) Both B and C.

Question

Quizplus · Accepted Answer

F1F1F1S1F1F1F10_T has two fewer ligands surrounding the metal (U) and the d-orbitals do not point directly at the remaining ligands, leading to a weaker metal-ligand bond. This results in a lower energy transition and therefore a lower wavelength of light absorbed. Therefore, E is the best choice.

Why Is Δ\DeltaΔ T Always Less Than Δ\DeltaΔ O? A) There Are Two More Ligands Surrounding the Metal

Why Is $\Delta$ _T Always Less Than $\Delta$ _O?
A) There Are Two More Ligands Surrounding the Metal