The complex ion [Cr(OH₂)₆]²⁺ has four unpaired electrons .This means that A) the complex is high-spin. B) the complex is diamagnetic. C) the water ligands are difficult to remove. D) the complex is low-spin. E) $\Delta \circ $ is very large.

Question

Quizplus · Accepted Answer

The presence of four unpaired electrons indicates that the complex is high-spin, which means that it does not pair electrons in its d orbitals until it has to, typically due to weaker field ligands or smaller crystal field splitting energy ($\Delta$).

The Complex Ion [Cr(OH2)6]2+ Has Four Unpaired Electrons Δ∘\Delta \circ Δ∘

The Complex Ion [Cr(OH₂)₆]²⁺ Has Four Unpaired Electrons $\Delta \circ$