Given: 2A(g)+ B(g)$\rightarrow$ C(g)+ D(g) When [A] = [B] = 0.10 M,The rate is 2.0 M.s^-¹; for [A] = [B] = 0.20,The rate is 8.0 M.s^-¹; and for[A] = 0.10 M,[B] = 0.20 M,The rate is 2.0 M.s^-¹.The rate law is A) rate = k[A]. B) rate = k[B]². C) rate = k[A][B]⁰. D) rate = k[A][B]. E) rate = k[A]².

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The Answer of Given: 2A(g)+ B(g)$\rightarrow$ C(g)+ D(g) When [A] = [B] = 0.10 M,The rate is 2.0 M.s^-¹; for [A] = [B] = 0.20,The rate is 8.0 M.s^-¹; and for[A] = 0.10 M,[B] = 0.20 M,The rate is 2.0 M.s^-¹.The rate law is A) rate = k[A]. B) rate = k[B]². C) rate = k[A][B]⁰. D) rate = k[A][B]. E) rate = k[A]².

Given: 2A(g)+ B(g) →\rightarrow→ C(g)+ D(g) When [A] = [B] = 0

Given:
2A(g)+ B(g) $\rightarrow$ C(g)+ D(g)
When [A] = [B] = 0