The reaction 2NO(g)+ 2H₂(g)$\rightarrow$N₂(g)+ 2H₂O(g) Is first order in H₂ and second order in NO.Starting with equal concentrations of H₂ and NO,The rate after 25% of the H₂ has reacted is what percent of the initial rate? A) 75.0% B) 42.2% C) 6.25% D) 56.3% E) 1.56%

Question

Quizplus · Accepted Answer

The rate law for the reaction can be written as follows: rate = k[NO]^2[H₂] Since the concentration of H₂ is decreasing by 25%, the new concentration is 0.75 times the initial concentration. We can use this information to find the new rate: rate = k[NO]^2[H₂] rate' = k[NO]^2(0.75[H₂]) = 0.5625k[NO]^2[H₂] The new rate is 56.3% of the initial rate. Therefore, the answer is (D) 56.3%.

The Reaction 2NO(g)+ 2H2(g) →\rightarrow→ N2(g)+ 2H2O(g) Is First Order in H2 and Second Order

The Reaction
2NO(g)+ 2H₂(g) $\rightarrow$ N₂(g)+ 2H₂O(g)
Is First Order in H₂ and Second Order