How many g of CaCl₂ are needed to prepare 500.mL of a 0.375 M solution? A)0.188 g B)1.69 g C)3.00 g D)20.8 g E)37.0 g

Name: How many g of CaCl 2 are needed to prepare 500.mL of a 0.375 M solution? A)0.188 g B)1.69 g C)3.00 g D)20.8 g E)37.0 g
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Quizplus · Accepted Answer

To find the mass of CaCl2 needed, use the formula: mass = molarity × volume × molar mass. The molar mass of CaCl2 is approximately 110.98 g/mol. For a 0.375 M solution in 0.5 L, the calculation is: 0.375 mol/L × 0.5 L × 110.98 g/mol = 20.8 g.

How Many G of CaCl2 Are Needed to Prepare 500

How Many G of CaCl₂ Are Needed to Prepare 500