A 50.0 mL sample of a 12.0 M solution of HCl is diluted to 250.mL.What is the new concentration?
A)60.0 M
B)12.0 M
C)10.4 M
D)3.00 M
E)2.40 M

Question

Quizplus · Accepted Answer

The new concentration can be calculated using the dilution formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume, respectively. Substituting the given values: $12.0\,M \times 50.0\,mL = C_2 \times 250.0\,mL$. Solving for $C_2$ gives $C_2 = \frac{12.0\,M \times 50.0\,mL}{250.0\,mL} = 2.40\,M$.

A 500 ML Sample of a 12