How many moles of solute are present in 12.0 L of 3.00 M HCl?
A)36.0 mol
B)4.00 mol
C)0.250 mol
D)3.00 mol
E)0.750 mol

Name: How many moles of solute are present in 12.0 L of 3.00 M HCl? A)36.0 mol B)4.00 mol C)0.250 mol D)3.00 mol E)0.750 mol
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Question

Quizplus · Accepted Answer

Moles of solute = Molarity x Volume

Given, 
Molarity of HCl = 3.00 M 
Volume of HCl = 12.0 L

Moles of HCl = 3.00 mol/L x 12.0 L = 36.0 mol

Therefore, the answer is A) 36.0 mol.

How Many Moles of Solute Are Present in 12