What is the molarity of a solution prepared by dissolving 10.0 g of acetone,C₃H₆O,in enough water to make 250.mL of solution? A)0.172 M B)0.689 M C)0.250 M D)0.0430 M E)0.0160 M

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of acetone:

m (g) = 10.0 g 
M (g/mol) = 58.08 g/mol (molar mass of acetone)
n (mol) = m/M = 10.0 g / 58.08 g/mol = 0.172 mol

Then, we need to calculate the molarity (M) of the solution:

M = n/V = 0.172 mol / 0.250 L = 0.689 M

Therefore, the molarity of the solution is 0.689 M, which corresponds to choice B.

What Is the Molarity of a Solution Prepared by Dissolving