What is the molarity of a solution prepared by dissolving 10.0 g of acetone,C₃H₆O,in enough water to make 125 mL of solution? A)4.65 M B)1.38 M C)0.0465 M D)0.0214 M E)0.0125 M

Question

Quizplus · Accepted Answer

To find the molarity of the solution, we need to first calculate the number of moles of acetone present in the solution.

Number of moles = Mass of solute / Molar mass of solute

Molar mass of acetone = 2 x Atomic mass of carbon + 6 x Atomic mass of hydrogen + Atomic mass of oxygen
= (2 x 12.01 g/mol) + (6 x 1.01 g/mol) + 16.00 g/mol
= 58.08 g/mol

Number of moles of acetone = 10.0 g / 58.08 g/mol
= 0.172 moles

Volume of solution = 125 mL = 0.125 L

Molarity = Number of moles / Volume of solution
= 0.172 moles / 0.125 L
= 1.376 M

Thus, the molarity of the solution is 1.38 M (rounded to two decimal places).

The correct answer is choice B, 1.38 M.

What Is the Molarity of a Solution Prepared by Dissolving