Calculate the freezing point of a 0.08500 m aqueous solution of NaNO₃. The molal freezing-point-depression constant of water is 1.86°C/m. A)0.0425 B)-0.0790 C)0.0790 D)-0.158 E)-0.316

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The freezing point depression is calculated using the formula ΔTf = i * Kf * m, where i is the van't Hoff factor (2 for NaNO3), Kf is the freezing-point-depression constant (1.86°C/m), and m is the molality (0.08500 m). ΔTf = 2 * 1.86 * 0.08500 = 0.316°C. The freezing point of water is 0°C, so the new freezing point is 0 - 0.316 = -0.316°C.

Calculate the Freezing Point of a 0