At 20°C, a 2.32 M aqueous solution of ammonium chloride has a density of 1.0344 g/mL. What is the molality of ammonium chloride in the solution? The formula weight of NH₄Cl is 53.50 g/mol. A)2.55 B)0.0449 C)2.32 D)0.446 E)12.00

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Quizplus · Accepted Answer

To find molality, we need moles of solute per kg of solvent. First, calculate the mass of the solution using its density (1.0344 g/mL) and volume (1 L for 2.32 moles). Then, subtract the mass of NH4Cl (2.32 moles * 53.50 g/mol) from the total mass to find the mass of the solvent. Finally, divide the moles of NH4Cl by the mass of the solvent in kg.