A solution is prepared by dissolving 10.0 g of benzene (C₆H₆)in 282 g of carbon tetrachloride (CCl₄). The concentration of benzene in this solution is ________ molal. The molar masses of C₆H₆ and CCl₄ are 78.1 g/mol and 154 g/mol, respectively. A)4.54 × 10^-4 B)0.454 C)0.0654 D)0.0342 E)3.42

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Quizplus · Accepted Answer

Molality is calculated as moles of solute per kilogram of solvent. Moles of benzene = 10.0 g / 78.1 g/mol = 0.128 mol. Mass of CCl₄ in kg = 282 g / 1000 = 0.282 kg. Molality = 0.128 mol / 0.282 kg = 0.454 mol/kg.

A Solution Is Prepared by Dissolving 10