A solution is prepared by dissolving 11.0 g of NH₃ in 250.0 g of water. The density of the resulting solution is 0.974 g/mL. The mole fraction of NH₃ in the solution is ________. A)0.0440 B)0.0445 C)0.940 D)0.922 E)16.8

Question

Quizplus · Accepted Answer

To find the mole fraction of NH₃, calculate the moles of NH₃ and water. Moles of NH₃ = 11.0 g / 17.03 g/mol = 0.646 mol. Moles of water = 250.0 g / 18.02 g/mol = 13.88 mol. Mole fraction of NH₃ = 0.646 / (0.646 + 13.88) = 0.0445.

A Solution Is Prepared by Dissolving 11