A solution is prepared by dissolving 23.7 g of CaCl₂ in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl₂ in this solution is ________ molal. A)0.214 B)0.569 C)5.70 D)63.2 E)1.76

Question

Quizplus · Accepted Answer

First, we need to calculate the moles of CaCl2 in the solution:

moles of CaCl2 = (23.7 g) / (110.98 g/mol) = 0.2136 mol

Next, we need to calculate the mass of water in the solution:

mass of water = (375 g) - (23.7 g) = 351.3 g

Finally, we can use the following equation to calculate the molality of the solution:

molality = moles of solute / mass of solvent (in kg)

mass of solvent = 351.3 g = 0.3513 kg

molality = 0.2136 mol / 0.3513 kg = 0.5688 mol/kg ≈ 0.569 molal

Therefore, the answer is B.

A Solution Is Prepared by Dissolving 23