A solution is prepared by dissolving 15.0 g of NH₃ in 250.0 g of water. The density of the resulting solution is 0.974 g/mL. The molality of NH₃ in the solution is ________ m. A)0.00353 B)0.882 C)60.0 D)3.24 E)3.53

Question

Quizplus · Accepted Answer

Molality (m) is calculated as moles of solute per kilogram of solvent. First, calculate moles of NH₃: 15.0 g / 17.03 g/mol = 0.880 moles. Then, convert 250.0 g of water to kilograms: 250.0 g = 0.250 kg. Finally, calculate molality: 0.880 moles / 0.250 kg = 3.52 m, which rounds to 3.53 m.

A Solution Is Prepared by Dissolving 15