What is the concentration (M)of 39.88 mL of an unknown NaOH solution if it required 46.08 mL of 0.6592 M HCl to neutralize?
A)0.7617
B)2788
C)1211
D)1.313
E)1.211

Question

Quizplus · Accepted Answer

The neutralization reaction between NaOH and HCl is a 1:1 molar ratio. Using the formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of HCl, and M2 and V2 are the molarity and volume of NaOH, we can solve for M2: (0.6592 M)(46.08 mL) = (M2)(39.88 mL). Solving for M2 gives approximately 0.7617 M.

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