The molarity (M)of an aqueous solution containing 22.5 g of sucrose (C₁₂H₂₂O₁₁)in 35.5 mL of solution is ________. A)0.0657 B)1.85 × C)1.85 D)3.52 E)0.104

Question

Quizplus · Accepted Answer

To calculate the molarity of sucrose, we need to first find the number of moles of sucrose in the solution, which can be calculated as:

Number of moles = Mass of solute / Molar mass of solute

Molar mass of sucrose (C12H22O11) = 12(12.01 g/mol) + 22(1.01 g/mol) + 11(16.00 g/mol) = 342.3 g/mol

Number of moles of sucrose = 22.5 g / 342.3 g/mol = 0.0656 mol

Next, we need to find the volume of the solution in liters, which can be calculated as:

Volume (in L) = Volume (in mL) / 1000

Volume (in L) = 35.5 mL / 1000 = 0.0355 L

Finally, we can calculate the molarity of the solution as:

Molarity = Number of moles / Volume (in L) = 0.0656 mol / 0.0355 L = 1.85 M

Therefore, the answer is C) 1.85.

The Molarity (M)of an Aqueous Solution Containing 22