Question 1

A rectangular water tank is 14.5 cm long and 4.63 cm wide. If 368.5 g of water completely fills the tank, the height of the tank is ________ cm. (Assume the density of water is 1.000 g/ml.)
A)6.45
B)5.49
C)14.0
D)3.68
E)4.62

Accepted Answer

The volume of the water tank can be found by multiplying its length, width, and height. Let's represent the height of the tank by "h".

Volume of tank = length x width x height
V = 14.5 cm x 4.63 cm x h
V = 67.0855h cm^3

We know that the density of water is 1.000 g/ml, which means that 1 cm^3 of water is equal to 1 gram. Therefore, the mass of the water in the tank is equal to its volume in cm^3.

Mass of water = volume of water = 368.5 g

We can use this information to find the height of the tank.

V = m/density
67.0855h = 368.5 g / 1.000 g/cm^3
h = 5.49 cm

Therefore, the height of the tank is 5.49 cm.

Question 2

The correct result (indicating the proper number of significant figures)of the following addition is ________. 12
1.2
0.12
+ 0.012
A)13
B)13.3
C)13.33
D)13.332
E)none of the above

Accepted Answer

The answer of The correct result (indicating the proper number...

Question 3

The output of a plant is 4335 pounds of ball bearings per week (five days). If each ball bearing weighs 0.0113 g, how many ball bearings does the plant make in a single day? (Indicate the number in proper scientific notation with the appropriate number of significant figures.) A)3.84 × 10⁵ B)7.67 × 10⁴ C)867 D)3.48 × 10⁷ E)2.91 × 10⁶

Accepted Answer

The answer of The output of a plant is 4335...

Question 4

There are ________ ng in a pg.
A)0.001
B)1000
C)0.01
D)100
E)10

Accepted Answer

A nanogram (ng) is one billionth of a gram (10^-9 g) and a picogram (pg) is one trillionth of a gram (10^-12 g). Therefore, there are 1000 ng in a pg (10^-12 g ÷ 10^-9 g/ng = 1000 ng/pg).

Question 5

A 4.369 g sample of metal is placed in a flask. Water is added to the flask and the total volume in the flask is read to be 126.4 ml. The mass of the water, flask, and metal is 268.5 g. If the mass of the flask is 139.3 g and the density of water is 1.000 g/mL, the density of the solid is ________ g/cm³. A)0.366 B)1.56 C)0.641 D)2.78 E)3.21

Accepted Answer

To find the density of the solid, we first need to calculate the volume of the metal. We can do this by subtracting the volume of water from the total volume in the flask. The mass of the water can be found by subtracting the mass of the flask and metal from the total mass, then using the density of water to find its volume. The density of the metal is then the mass of the metal divided by its volume.1. Mass of water + flask + metal = 268.5 g2. Mass of flask = 139.3 g3. Mass of metal = 4.369 g4. Total volume in flask = 126.4 mLMass of water = Total mass - (Mass of flask + Mass of metal) = 268.5 g - (139.3 g + 4.369 g) = 124.831 gSince the density of water is 1.000 g/mL, the volume of water is 124.831 mL.Volume of metal = Total volume - Volume of water = 126.4 mL - 124.831 mL = 1.569 mLDensity of metal = Mass of metal / Volume of metal = 4.369 g / 1.569 mL = 2.78 g/cm³

Question 6

There are ________ significant figures in the answer to the following computation: 
A)1
B)2
C)3
D)4
E)5

Accepted Answer

The answer of There are ________ significant figures in the...

Question 7

The correct answer (reported to the proper number of significant figures)to the following is ________. 12.75 × 1.3621 = ________
A)17.367
B)17.40
C)17.37
D)17.4
E)17.0

Accepted Answer

To multiply these two numbers, we follow the rules of significant figures:

- The result should have the same number of significant figures as the number with the least amount of significant figures in the calculation. 
- In multiplication and division, we round the result to the same number of significant figures as the number with the least amount of significant figures.

In this case:

- 12.75 has four significant figures.
- 1.3621 has five significant figures.

Therefore, the result should have four significant figures.

When we multiply the two numbers, we get:

12.75 × 1.3621 = 17.367375

To round this to four significant figures, we look at the fifth significant figure (7) and apply the rounding rule:

- If the fifth significant figure is 5 or greater, we round up the fourth significant figure.
- If the fifth significant figure is less than 5, we leave the fourth significant figure unchanged.

In this case, the fifth significant figure is 7, which is greater than 5. Therefore, we round up the fourth significant figure (6) to 7:

17.367375 rounds to 17.37 when rounded to four significant figures.

Therefore, the answer is C.

Question 8

There should be ________ significant figures in the answer to the following computation. 
A)1
B)2
C)3
D)4
E)5

Accepted Answer

The answer of There should be ________ significant figures in...

Question 9

The correct answer (reported to the proper number of significant figures)to the following is ________. (12.67 + 19.2)(3.99)/ (1.36 + 11.366)= ________ A)9.99851 B)9.9985 C)9.999 D)1.00 × 10¹ E)none of the above

Accepted Answer

The answer of The correct answer (reported to the proper...

Question 10

The quantity 1.0 mg/cm² is the same as 1.0 × ________ kg/m². A)10^-4 B)10² C)10^-6 D)10^-2 E)10⁴

Accepted Answer

1 mg = 0.000001 kg (conversion from mg to kg) 1 cm = 0.01 m (conversion from cm to m) 1² = 10^-12 (conversion from ² to base units) So, putting it all together: 1.0 mg/cm² = 0.000001 kg / (0.01 m * 10^-12) = 1.0 × 10^11 kg/m² Therefore, the answer is D) 10^-2.

Question 11

The density of a 167.4 g sample of magnesium having a volume of 96.32 mL is ________ g/cm³. A)0.5754 B)7128 C)3.625 D)2.663 E)1.738

Accepted Answer

The answer of The density of a 167.4 g sample...

Question 12

The volume of a regular cylinder is V =πr²h. Using the value 3.1416 for the constant π, the volume (cm³)of a cylinder of radius 2.34 cm and height 19.91 cm expressed to the correct number of significant figures is ________. A)342.49471 B)342.495 C)342.49 D)343 E)342

Accepted Answer

The answer of The volume of a regular cylinder is...

Question 13

An iron mine produces 1.67 × 10⁴ tons of raw ore per day. If the ore is 26.39% elemental iron, the mine produces ________ pounds of elemental iron per year. (Assume the mine operates 365 days per year.) A)1.221 × 10¹⁰ B)8.814 × 10⁶ C)3.217 × 10⁹ D)1.611 × 10⁶ E)3.66 × 10¹¹

Accepted Answer

First, calculate the annual production of raw ore: 1.67 × 10^4 tons/day × 365 days/year = 6.0955 × 10^6 tons/year. Then, calculate the annual production of elemental iron: 6.0955 × 10^6 tons/year × 0.2639 = 1.608 × 10^6 tons/year. Convert tons to pounds (1 ton = 2000 pounds): 1.608 × 10^6 tons/year × 2000 pounds/ton = 3.216 × 10^9 pounds/year, which is approximately 3.217 × 10^9 pounds/year.

Question 14

The distance from the Earth to the Moon is approximately 240,000 miles. If a rocket travels at a speed of 7.50 km/sec, it will take ________ days to travel between the Earth and Moon.
A)0.60
B)1.7
C)3.9
D)7.3
E)5.6

Accepted Answer

The distance from the Earth to the Moon is approximately 240,000 miles. If a rocket travels at a speed of 7.50 km/sec, it will take 0.60 days to travel between the Earth and Moon.

Question 15

The number 1.00430 has ________ significant figures.
A)2
B)3
C)5
D)6
E)4

Accepted Answer

The zeros between the significant figures are also significant. Therefore, the number has 6 significant figures.

Question 16

The correct result (indicating the proper number of significant figures)of the following calculation of the molecular mass for H₂SO₄ is ________. 4 × 15.9994 + 32.066 + 2 × 1.0079 A)98.08 B)98.079 C)98.074 D)98.838 E)98.84

Accepted Answer

The answer of The correct result (indicating the proper number...

Question 17

1.55 kg/m³ is equivalent to ________ g/L. A)3.58 × 10¹² B)1.95 × 10³ C)6.83 D)1.60 × 10⁹ E)1.55

Accepted Answer

1 kg/m³ is equivalent to 1 g/L. Therefore, 1.55 kg/m³ is equivalent to 1.55 g/L.

Question 18

The density of mercury is 13.6 g/cm³. The density of mercury is ________ kg/m³. A)1.36 × 10^-2 B)1.36 × 10⁴ C)1.36 × 10⁸ D)1.36 × 10^-5 E)1.36 × 10^-4

Accepted Answer

To convert g/cm3 to kg/m3, we need to multiply by 1000 (to convert from grams to kilograms) and by 1003 (to convert from cubic centimeters to cubic meters). Therefore, the density of mercury in kg/m3 is:
13.6 g/cm3 × 1000 kg/g × 1000 cm3/m3 = 1.36 × 107 kg/m3. 
The only choice that matches this value is B.

Question 19

________ significant figures should be retained in the result of the following calculation. 
A)1
B)2
C)3
D)4
E)5

Accepted Answer

The answer of ________ significant figures should be retained in...

Question 20

The correct result (indicating the proper number of significant figures)of the following problem is ________. A)113.73635 B)113.736 C)113.74 D)113.7 E)1.1 × 10²

Accepted Answer

The answer of The correct result (indicating the proper number...

Quiz 1: Introduction: Matter and Measurement

A rectangular water tank is 14.5 cm long and 4.63 cm wide. If 368.5 g of water completely fills the tank, the height of the tank is ________ cm. (Assume the density of water is 1.000 g/ml.)

The correct result (indicating the proper number of significant figures) of the following addition is ________. 12 1.2 0.12 + 0.012

The output of a plant is 4335 pounds of ball bearings per week (five days) . If each ball bearing weighs 0.0113 g, how many ball bearings does the plant make in a single day? (Indicate the number in proper scientific notation with the appropriate number of significant figures.)

There are ________ ng in a pg.

There are ________ significant figures in the answer to the following computation:

The correct answer (reported to the proper number of significant figures) to the following is . 12.75 × 1.3621 =

There should be ________ significant figures in the answer to the following computation.

The correct answer (reported to the proper number of significant figures) to the following is . (12.67 + 19.2) (3.99) / (1.36 + 11.366) =

The quantity 1.0 mg/cm² is the same as 1.0 × ________ kg/m².

The density of a 167.4 g sample of magnesium having a volume of 96.32 mL is ________ g/cm³.

The volume of a regular cylinder is V =πr²h. Using the value 3.1416 for the constant π, the volume (cm³) of a cylinder of radius 2.34 cm and height 19.91 cm expressed to the correct number of significant figures is ________.

An iron mine produces 1.67 × 10⁴ tons of raw ore per day. If the ore is 26.39% elemental iron, the mine produces ________ pounds of elemental iron per year. (Assume the mine operates 365 days per year.)

The distance from the Earth to the Moon is approximately 240,000 miles. If a rocket travels at a speed of 7.50 km/sec, it will take ________ days to travel between the Earth and Moon.

The number 1.00430 has ________ significant figures.

The correct result (indicating the proper number of significant figures) of the following calculation of the molecular mass for H₂SO₄ is ________. 4 × 15.9994 + 32.066 + 2 × 1.0079

1.55 kg/m³ is equivalent to ________ g/L.

The density of mercury is 13.6 g/cm³. The density of mercury is ________ kg/m³.

________ significant figures should be retained in the result of the following calculation.

The correct result (indicating the proper number of significant figures) of the following problem is ________.

Quiz 1: Introduction: Matter and Measurement

A rectangular water tank is 14.5 cm long and 4.63 cm wide. If 368.5 g of water completely fills the tank, the height of the tank is ________ cm. (Assume the density of water is 1.000 g/ml.)

The correct result (indicating the proper number of significant figures) of the following addition is ________. 12 1.2 0.12 + 0.012

The output of a plant is 4335 pounds of ball bearings per week (five days) . If each ball bearing weighs 0.0113 g, how many ball bearings does the plant make in a single day? (Indicate the number in proper scientific notation with the appropriate number of significant figures.)

There are ________ ng in a pg.

There are ________ significant figures in the answer to the following computation:

The correct answer (reported to the proper number of significant figures) to the following is ________. 12.75 × 1.3621 = ________

There should be ________ significant figures in the answer to the following computation.

The correct answer (reported to the proper number of significant figures) to the following is ________. (12.67 + 19.2) (3.99) / (1.36 + 11.366) = ________

The quantity 1.0 mg/cm2 is the same as 1.0 × ________ kg/m2.

The density of a 167.4 g sample of magnesium having a volume of 96.32 mL is ________ g/cm3.

The volume of a regular cylinder is V =πr2h. Using the value 3.1416 for the constant π, the volume (cm3) of a cylinder of radius 2.34 cm and height 19.91 cm expressed to the correct number of significant figures is ________.

An iron mine produces 1.67 × 104 tons of raw ore per day. If the ore is 26.39% elemental iron, the mine produces ________ pounds of elemental iron per year. (Assume the mine operates 365 days per year.)

The distance from the Earth to the Moon is approximately 240,000 miles. If a rocket travels at a speed of 7.50 km/sec, it will take ________ days to travel between the Earth and Moon.

The number 1.00430 has ________ significant figures.

The correct result (indicating the proper number of significant figures) of the following calculation of the molecular mass for H2SO4 is ________. 4 × 15.9994 + 32.066 + 2 × 1.0079

1.55 kg/m3 is equivalent to ________ g/L.

The density of mercury is 13.6 g/cm3. The density of mercury is ________ kg/m3.

________ significant figures should be retained in the result of the following calculation.

The correct result (indicating the proper number of significant figures) of the following problem is ________.

The correct answer (reported to the proper number of significant figures) to the following is . 12.75 × 1.3621 =

The correct answer (reported to the proper number of significant figures) to the following is . (12.67 + 19.2) (3.99) / (1.36 + 11.366) =

The quantity 1.0 mg/cm² is the same as 1.0 × ________ kg/m².

The density of a 167.4 g sample of magnesium having a volume of 96.32 mL is ________ g/cm³.

The volume of a regular cylinder is V =πr²h. Using the value 3.1416 for the constant π, the volume (cm³) of a cylinder of radius 2.34 cm and height 19.91 cm expressed to the correct number of significant figures is ________.

An iron mine produces 1.67 × 10⁴ tons of raw ore per day. If the ore is 26.39% elemental iron, the mine produces ________ pounds of elemental iron per year. (Assume the mine operates 365 days per year.)

The correct result (indicating the proper number of significant figures) of the following calculation of the molecular mass for H₂SO₄ is ________. 4 × 15.9994 + 32.066 + 2 × 1.0079

1.55 kg/m³ is equivalent to ________ g/L.

The density of mercury is 13.6 g/cm³. The density of mercury is ________ kg/m³.