For the reaction What is D_rS^o? A)262.5 J/mol ∙ K B)-85.1 J/mol ∙ K C)-164.7 J/mol ∙ K D)164.7 J/mol ∙ K E)85.1 J/mol ∙ K

Question

Quizplus · Accepted Answer

D_rS^o is the standard entropy change for the reaction. Using the formula ΔS° = ΣS°(products) - ΣS°(reactants), we get: ΔS° = (2 × 205.2 J/mol∙K) - (4 × 186.2 J/mol∙K) - (1 × 213.7 J/mol∙K) + (2 × 186.2 J/mol∙K) = -164.7 J/mol∙K (rounded to one decimal place). Therefore, the answer is D, -164.7 J/mol∙K.

For the Reaction What Is DrSo?

For the Reaction What Is D_rS^o?