If the enthalpy of vaporization of chloromethane,CH₃Cl,is 21.5 kJ/mol at the normal boiling point,249 K,calculate Δ_vap S°. A)86.3 J mol^-1 K^-1 B)5.35 J mol^-1 K^-1 C)11.6 J mol^-1 K^-1 D)896 J mol^-1 K^-1

Question

Quizplus · Accepted Answer

The equation for calculating ΔS1U1B1vapS1U1B0 S° is:
ΔS1U1B1vapS1U1B0 S° = ΔH1U1B1vapS1U1B0 / T

Plugging in the given values, we get:
ΔS1U1B1vapS1U1B0 S° = 21.5 kJ/mol / 249 K

Converting kJ to J and simplifying, we get:
ΔS1U1B1vapS1U1B0 S° = 86.3 J molS1U1P1-1S1S1P0 KS1U1P1-1S1S1P0

Therefore, the best choice is A.

If the Enthalpy of Vaporization of Chloromethane,CH3Cl,is 21

If the Enthalpy of Vaporization of Chloromethane,CH₃Cl,is 21