Given the following information,calculate ΔH° (in kcal mol^-1)for: I(g)+ e^- → I^-(g) A)-633 kcal mol^-1 B)-450 kcal mol^-1 C)-71 kcal mol^-1 D)-696 kcal mol^-1 E)+712 kcal mol^-1

Question

Quizplus · Accepted Answer

From the given reaction, we see that one mole of iodine is reduced to form iodide ion while gaining one electron. Thus, the reaction is an electron gain reaction and the electron affinity of iodine is defined as the enthalpy change that occurs when one mole of iodine gains one electron to form iodide ion in the gas phase.

The electron affinity of iodine has a negative value, indicating that it is an exothermic process. Since the reaction given in the question is the reverse of electron affinity, the enthalpy change for this reaction will be positive.

The correct value of ΔH° for the given reaction can be obtained by reversing the sign of the electron affinity of iodine, which is given as +71 kcal mol^-1. Therefore, the correct answer is -71 kcal mol^-1.

Given the Following Information,calculate ΔH° (In Kcal Mol-1)for: I(g)+ E-

Given the Following Information,calculate ΔH° (In Kcal Mol^-1)for: I(g)+ E^-