Given the following information,calculate ΔH° (in kcal mol^-1)for: Cl(g)+ e^- → Cl^-(g) A)+ 83 kcal mol^-1 B)-83 kcal mol^-1 C)161 kcal mol^-1 D)-112 kcal mol^-1 E)190 kcal mol^-1

Question

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The reaction involves the formation of a negative ion (Cl-), which is the reverse process of electron affinity. Since electron affinity is an exothermic process, it releases energy, which is equal to the enthalpy change of the reverse process. Therefore, ΔH° is expected to be negative. Option A, C, D, and E are positive, indicating an endothermic process. Option B is the only negative value, indicating an exothermic process.

Given the Following Information,calculate ΔH° (In Kcal Mol-1)for

Given the Following Information,calculate ΔH° (In Kcal Mol^-1)for