From the following thermochemical equations,calculate ΔrH° for the reaction:
SO2(g) + NO2(g) → SO3(g) + NO(g)
2 SO2(g) + O2(g) → 2 SO3(g) ΔrH° = -197.8 kJ/mol
2 NO(g) + O2(g) → 2 NO2(g) ΔrH° = -114.14 kJ/mol
A) -83.66 kJ /mol
B) -311.9 kJ/mol
C) +155.9 kJ/mol
D) -155.9 kJ/mol
E) -41.83 kJ/mol
Correct Answer:
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