What is the work done in joules by the system when H₂ expands against a constant pressure of 75 atm at 45.3 °C? The change in volume is 24.0 L. A)1.8 × 10^{3 J} B)-8.2 × 10^{4 J} C)8.2 × 10^{4 J} D)1.8 × 10^{5 J} E)-1.8 × 10^{5 J}

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Quizplus · Accepted Answer

The work done by the system is calculated using the formula W = -PΔV. Converting pressure from atm to Pa (1 atm = 101325 Pa) and volume from L to m³ (1 L = 0.001 m³), we get W = -(75 atm * 101325 Pa/atm) * (24.0 L * 0.001 m³/L) = -1.8 × 10⁵ J.

What Is the Work Done in Joules by the System