If 5.97 mL of a solution of NaCl contains 2.54 mg of sodium ion,what is the molarity of the sodium chloride solution? A)0.425 M B)1.85 × 10^-2 M C)1.85 × 10^-5 M D)7.28 × 10^-3 M E)0.102 M

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Quizplus · Accepted Answer

To find the molarity, first convert 2.54 mg of sodium ion to moles (2.54 mg = 0.00254 g; moles = 0.00254 g / 22.99 g/mol = 1.105 × 10^-4 mol). Since NaCl dissociates into Na+ and Cl-, the moles of Na+ equals the moles of NaCl. Convert 5.97 mL to liters (5.97 mL = 0.00597 L). Molarity = moles/volume = 1.105 × 10^-4 mol / 0.00597 L = 1.85 × 10^-2 M.

If 597 ML of a Solution of NaCl Contains 2