If 85.6 mL of a 6.75 M solution are diluted to 6.20 L with water,what is the concentration of the final solution?
A)6.75 (6.20/85.6)M
B)6.75 (8.56/6.20)M
C)6.75 (6200/85.6)M
D)6.75 (85.6/6200)M
E)8.56 (6.20/6.75)M

Question

Quizplus · Accepted Answer

The concentration of the final solution can be found using the dilution formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume, respectively. Rearranging for $C_2$, we get $C_2 = C_1 \times (V_1/V_2)$. Substituting the given values, $C_2 = 6.75 \times (85.6/6200)$ M, which matches choice D.

If 856 ML of a 6