A 9.6-V battery is connected in series with a switch,6.0-Ω resistor and coil.What energy is stored in the coil when the current is 1.6 A? The time constant is 4.3 × 10−⁴ s. A) 3.3E-3 J B) 6.6E-3 J C) 4.1E-3 J D) 1.1E-3 J E) 1.3E-3 J

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Quizplus · Accepted Answer

The energy stored in an inductor is given by the equation E = 1/2 * L * I^2, where L is the inductance of the coil and I is the current flowing through it. In this problem, we are given the current (I = 1.6 A) and the time constant (tau = 4.3 * 10^-4 s), but we are not given the inductance (L). However, we can use the time constant to find the inductance, since tau = L/R, where R is the resistance of the circuit. In this problem, the resistance is 6.0 ohms, so the inductance is L = tau * R = 4.3 * 10^-4 s * 6.0 ohms = 2.58 * 10^-3 H. Now that we have the inductance, we can calculate the energy stored in the coil: E = 1/2 * L * I^2 = 1/2 * 2.58 * 10^-3 H * (1.6 A)^2 = 3.3 * 10^-3 J. Therefore, the correct answer is A.

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