An air-core inductor has 2000 turns/m and an internal volume of 1.3 cm³.What is its inductance? A) 6.5 μH B) 2.6 mH C) 0.33 H D) 65 μH E) Insufficient information is given.

Question

Quizplus · Accepted Answer

The inductance of an air-core inductor can be calculated using the formula L = (μ₀ * N² * A * l), where μ₀ is the permeability of free space (4π x 10⁻⁷ H/m), N is the number of turns per meter, A is the cross-sectional area, and l is the length. Given the internal volume, we can find the cross-sectional area and length, and then calculate the inductance.

An Air-Core Inductor Has 2000 Turns/m and an Internal Volume