A Ferris wheel,rotating initially at an angular speed of 0.500 rad/s,accelerates over a 7.00-s interval at a rate of 0.0500 rad/s².What angular displacement does the Ferris wheel undergo in this 7.00-s interval? A) 4.48 rad B) 2.50 rad C) 4.73 rad D) 0.500 rad

Question

Quizplus · Accepted Answer

We can use the formula

θ = ωi*t + (1/2) * α * t^2

where 
ωi = 0.500 rad/s (initial angular speed) 
α = 0.0500 rad/s^2 (angular acceleration) 
t = 7.00 s (time interval)

Plugging in the values, we get

θ = (0.500 rad/s)*(7.00 s) + (1/2)*(0.0500 rad/s^2)*(7.00 s)^2 
θ ≈ 4.73 rad

Therefore, the Ferris wheel undergoes an angular displacement of approximately 4.73 radians during this 7.00-second interval. The correct answer is (C).

A Ferris Wheel,rotating Initially at an Angular Speed of 0