A Ferris wheel,rotating initially at an angular speed of 0.16 rad/s,accelerates over a 7.0-s interval at a rate of 0.050 rad/s².What is its angular speed after this 7.0-s interval? A) 0.46 rad/s B) 0.85 rad/s C) 0.51 rad/s D) 1.2 rad/s

Question

Quizplus · Accepted Answer

Using the formula:

ω = ω0 + αt

where 
ω = final angular speed 
ω0 = initial angular speed = 0.16 rad/s 
α = angular acceleration = 0.050 rad/s² 
t = time interval = 7.0 s

Substituting the values:

ω = 0.16 + (0.050)(7.0) 
ω = 0.51 rad/s

Therefore, the final angular speed of the Ferris wheel after the 7.0-s interval is 0.51 rad/s. 
The correct choice is C.

A Ferris Wheel,rotating Initially at an Angular Speed of 0