What is the boiling-point change for a solution containing 0.723 mol of naphthalene (a nonvolatile,nonionizing compound)in 250.g of liquid benzene? (K_b = 2.53°C/m for benzene) A)7.32 °C B)3.50 °C C)0.457 °C D)0.87 °C E)1.829 °C

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The boiling-point change is given by the equation:$$\Delta T_b = K_b 	imes m$$where:* $\Delta T_b$ is the boiling-point change in °C* $K_b$ is the boiling-point elevation constant in °C/m* $m$ is the molality of the solution in mol/kgIn this problem, we have:* $K_b$ = 2.53 °C/m* $m$ = 0.723 mol / 0.250 kg = 2.89 mol/kgSubstituting these values into the equation, we get:$$\Delta T_b = 2.53 °C/m 	imes 2.89 mol/kg = 7.32 °C$$Therefore, the boiling-point change is 7.32 °C.

What Is the Boiling-Point Change for a Solution Containing 0