What is the freezing point of a 0.19 m solution of glucose,C₆H₁₂O₆,in water? (K_f for water is 1.858°C/m.) A)0.18°C B)0.35°C C)-0.35°C D)-0.18°C E)-0.71°C

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Quizplus · Accepted Answer

The freezing point depression is calculated using ΔTf = i * Kf * m. For glucose, i = 1. ΔTf = 1 * 1.858°C/m * 0.19 m = 0.353°C. The freezing point of pure water is 0°C, so the solution's freezing point is 0°C - 0.353°C = -0.35°C.

What Is the Freezing Point of a 0