Oxygen gas makes up 21 % of the atmosphere by volume.What is the solubility of O₂(g)in water at 25°C if the atmospheric pressure is 741 mmHg? The Henry's law constant for oxygen gas at 25°C is 1.3 * 10^-³ mol/L·atm. A)2.7 * 10^-4 M B)1.3 * 10^-3 M C)6.2 * 10^-3 M D)9.6 * 10^-3 M E)0.96 M

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Quizplus · Accepted Answer

To find the solubility of O2 in water, use Henry's Law: S = kH * P. First, convert the partial pressure of O2 to atm: (21% of 741 mmHg) = 155.61 mmHg = 0.204 atm. Then, S = (1.3 * 10^-3 mol/L·atm) * (0.204 atm) = 2.7 * 10^-4 M.

Oxygen Gas Makes Up 21 % of the Atmosphere by Volume.What